Answer:
Step-by-step explanation:
Presuming represents the length of the box (which you should have specified), your volume function:
is correct.
V(x)=-x^3+33x^2-90x=0
Obviously, in order to have a box, all three dimensions must be positive numbers.
Since the height is 3 less than the length, the length must be greater than 3 so that the height will be greater than zero. Since the sum of length and width is 30, the length must be less than 30. Hence, the possible range of values for is
If you know enough calculus to be able to take the derivative of this function, set the first derivative equal to zero and solve. You will obtain two possible extrema. Only one of these extrema will lie in the the acceptable range of values,
If you don't know the Calculus, then the best you can do is to graph the function and eyeball it.
Step-by-step explanation:or 3, 19, 9, 7, 27, 4, 8, 15, 3, 11. ... There are 10 total numbers, so the 5th and 6th numbers are used to ... The 2 middle numbers only need to be averaged when the data set ... For instance, if your set has 21, 9, 14, 3, 11, 33, 5, 9, 16, 21, 5, 9, what is the mode?
Answer:
I need a liitle bit more information
Step-by-step explanation:
Answer:
<h2>This value is called the common difference</h2>
Step-by-step explanation:
The common difference is the constant value which is repeatedly added to each term in an arithmetic sequence to obtain the next term, it is basically the difference between consecutive numbers
To find the common difference we can subtract the previous term from the first time or the second to the last term from the last term, the idea of finding the common difference is basically subtracting the previous term form the subsequent term.
i don't think it exists anymore sorry
