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navik [9.2K]
3 years ago
9

Find 3 consecutive integets such that the sum of the first two integers is 24 more than the third. ​

Mathematics
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

breath

Step-by-step explanation:

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Please help I’m so close to passing math
kirill115 [55]

Answer:

$0.14 per ounce of salsa

Step-by-step explanation:

2.80/20

Move decimal to make the number a whole number

(Have to move the decimal the same amount of spaces)

28/200

0.14

Hope this helps. Have a nice day

8 0
3 years ago
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Which of these values cannot represent the probability of an event happening?
ololo11 [35]

Answer:

D.

Step-by-step explanation:

The last option, 1.2, cannot represent the probability of an event happening since it is more than 100% (120%). And event cannot have a higher probability of happening than "happening".

A. 0.33 is a valid response, since it represents 33%.

B. 56% is also a valid response.

C. 7/8 is also a valid response since it represents 0,875 or 87,5%.

Hope it helped,

BiologiaMagister

6 0
3 years ago
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Pls help what do I put
aleksandr82 [10.1K]

Answer:

m+m×0.15

because it increased by 15%

you get m's 15% if you multiply it with 0.15

7 0
3 years ago
50 pts-----Is there a special way to solve a question like this (without calculator)
andreyandreev [35.5K]
The only way to do it is 1.8x1.8x1.8x1.8x1.8x1.8x1.8x1.8x1.8. Or just use a calculator. Sorry to let you down
4 0
3 years ago
Find the maximum and minimum values of the function below on the horizontal span from 1 to 5. Be sure to include endpoint maxima
mote1985 [20]

Answer:

Max = 86; min = 36.54

Step-by-step explanation:

f(x) = x^{2} + \dfrac{85}{x}

Step 1. Find the critical points.

(a) Take the derivative of the function.

f'(x) = 2x - \dfrac{85}{x^{2}}

Set it to zero and solve.

\begin{array}{rcl}2x - \dfrac{85}{x^{2}} & = & 0\\\\2x^{3} - 85 & = & 0\\2x^{3} & = & 85\\\\x^{3} & = &\dfrac{85}{2}\\\\x & = & \sqrt [3]{\dfrac{85}{2}}\\\\& \approx & 3.490\\\end{array}\

(b) Calculate ƒ(x) at the critical point.  

f(3.490) = 3.490^{2} + \dfrac{85}{3.490} = 12.18 + 24.36 = 36.54

Step 2. Calculate ƒ(x) at the endpoints of the interval

f(1) = 1^{2} + \dfrac{85}{1} = 1 + 85 = 86\\\\f(5) = 5^{2} + \dfrac{85}{5} = 25 + 17 = 42

Step 3.Identify the maxima and minima.

ƒ(x) achieves its absolute maximum of 86 at x = 1 and its absolute minimum of 36.54 at x = 3.490

The figure below shows the graph of ƒ(x) from x = 1 to x = 5.

5 0
3 years ago
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