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Rama09 [41]
3 years ago
6

Find the center, vertices, and foci of the ellipse with equation x squared divided by 400 plus y squared divided by 625 = 1

Mathematics
2 answers:
Digiron [165]3 years ago
6 0

Answer:

Center: (0, 0); Vertices: (0, -25), (0, 25); Foci: (0, -15), (0, 15)

Step-by-step explanation:

<em><u>The center is (0,0)</u></em> because there is no (h,k)

<u><em>The vertices are (0, -25), (0, 25)</em></u> because we use the formula (x-h)^2/b^2 + (y-k)^2/a^2 = 1, since the y's denominator is larger.

<u><em>The foci are (0, -15), (0, 15)</em></u> because we use the formula a^2=b^2+c^2 to find the foci, a=625 and b=400, simplify to c=+ or - 15 and you get your foci.

Inessa05 [86]3 years ago
4 0

Answer:

x^2/400 + x^2/625

(x-0)^2/400) +(y-0^2/625)

x^2=400

X=sqrt. 400

x = 20

y^2=625

y = sqrt. 625

y= 25

a^2-c^2=b^2

sqrt 400-625 = c

20-25=c

The correct answer is c=-5

(-5,0)

(5,0)

Step-by-step explanation:

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