Answer: 64
Step-by-step explanation:
the Kids that answered correct in any of questions 1 and 2 got at least one right so subtract the highest number which is 81 students by all the general amount of them, 145 that’s 64.
The range is the set of all valid
y
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
,
∞
)
The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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Answer:
11
Step-by-step explanation:
apply pythagoras theorem