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2 years ago

Drag the correct symbol into the box to compare expessions 6^2-2^2___4(6+2) A.≠ B.=

Mathematics

1 answer:

Mnenie [13.5K]2 years ago

8 0

Simplify both sides to compare:

6^2 - 2^2 = 36-4 = 32

4(6+2) = 4 x 8 = 32

they are equal to each other.

Answer: B. =

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The point A(–1, 4) is translated five units right and three units down. Which rule describes the translation?

lozanna [386]

Answer: SECOND OPTION.

Step-by-step explanation:

Given the following point identified as "A":

$A(-1,4)$

You can identify that the x-coordinate of the point is:

$x=-1$

And its y-coordinate is:

$y=4$

According to the exercise, this point is translated five units right and three units down. This means that, in order to find the new coordinates, you need to add 5 to the original x-coordinate and subtract 3 from the original y-coordinate.

Therefore, you can conclude that the rule that best describe the translation of the point $A(-1,4)$ is the following:

$(x,y)$ → $(x+5,y-3)$

Then, the point translated is:

$A'(-1+5,\ 4-3)$ → $A'(4,1)$

6 0

3 years ago

Read 2 more answers

Number 5 pleaseeeeee

Korvikt [17]

The answer is C. y= 3/2 x. You can check by multiplying 3/2 by 3, if you get 7, it is correct

6 0

3 years ago

Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.

irina1246 [14]

Lagrange multipliers:

$L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)$

$L_x=y^2z^2+\lambda=0$
$L_y=2xyz^2+\lambda=0$
$L_z=2xy^2z+\lambda=0$
$L_\lambda=x+y+z-5=0$

$\lambda=-y^2z^2=-2xyz^2=-2xy^2z$

$-y^2z^2=-2xyz^2\implies y=2x$ (if $y,z\neq0$ )

$-y^2z^2=-2xy^2z\implies z=2x$ (if $y,z\neq0$ )

$-2xyz^2=-2xy^2z\implies z=y$ (if $x,y,z\neq0$ )

In the first octant, we assume $x,y,z>0$ , so we can ignore the caveats above. Now,

$x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2$

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of $f(1,2,2)=16$ .

We also need to check the boundary of the region, i.e. the intersection of $x+y+z=5$ with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force $f(x,y,z)=0$ , so the point we found is the only extremum.

4 0

3 years ago

Blhvjh gjfgfkytdkykdyrckhg

Dimas [21]

Answer:

tvubhgfyvug fyicvuui

Step-by-step explanation:

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8 0

3 years ago

What is an equation of the line that passes through point (5,-8) and is parallel to the line x+y=7

Igoryamba

Answer:

The line given is equal to y=-x+7 (Through rearranging)

To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):

-8=-5+c

c=-3

The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3

4 0

3 years ago