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ololo11 [35]
2 years ago
8

Pls explain why its a yes pleasee and thx u​

Mathematics
1 answer:
mixas84 [53]2 years ago
3 0
Because -5 is less than or equal to 0
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If the diameter of a circle is 6 what is the area
Ad libitum [116K]

Answer:

28.26

Step-by-step explanation:

A = pi radius squared

A = 3.14 x 9

A= 28.26

6 0
3 years ago
Read 2 more answers
There are 12 grams of sugar in 1/3 of a piece of candy. How much sugar is in 3/4
Mariana [72]
Hi! This problem be set up with a ratio or fraction. 12/.333 = x/.75
Cross multiply
9=.333x
divide by .333 on each side
giving you x=27
There are 27 grams of sugar in a 3/4 piece of candy
7 0
3 years ago
Solve the system using elimination,<br> 2x - 3y = - 19<br> 7x + 7y = 21
blagie [28]

Answer:

x = -2

y = 5

Step-by-step explanation:

2x - 3y = -19  ---------------------------(I)

7x+ 7y = 21  -----------------------------(II)

Multiply equation (I) by 7 and equation (II) by 3.Then add and so y will be eliminated and you will get the value of x

(I)*7              14x - 21y = - 133

(II)* 3           <u> 21x + 21y = 63  </u>        {Now add}

                   35x          = -70

                                x = -70/35

x = - 2

Plug in x = - 2 in equation (I)

2*(-2) - 3y = -19

-4 -  3y  = -19

     -3y = -19 + 4

     -3y = -15

         y = -15/-3

y = 5

8 0
3 years ago
Akin and ayo shared the sum of 200 in the ratio of 5:1 find the amount ago received
Elanso [62]

Total number of sharings = 5+1 = 6

600 / 6 = 33.33

So ayo  had one out of the 6  and received 33.33   answer

5 0
3 years ago
The third and the sixth term of a geometric progression are 24 and 64/9 respectively. Find
Ratling [72]

Answer:

Ai. Common ratio = 2/3

Aii. First term = 54

B. Sum of the first five terms = 422/3

Step-by-step explanation:

From the question given above, the following data were obtained:

3rd term (T3) = 24

6Th term (T6) = 64/9

First term (a) =?

Common ratio (r) =?

Sum of the first five terms​ (S5) =?

Ai. Determination of the common ratio (r).

T3 = ar²

T3 = 24

24 = ar²....... (1)

T6 = ar⁵

T6 = 64/9

64/9 = ar⁵......... (2)

The equation are:

24 = ar²....... (1)

64/9 = ar⁵......... (2)

Divide equation 2 by equation 1.

64/9 ÷ 24 = ar⁵ / ar²

64/9 × 1/24 = r³

8/27 = r³

Take the cube root of both side

r = 3√(8/27)

r = 2/3

Thus, the common ratio is 2/3

Aii. Determination of the first term (a).

T3 = ar²

3rd term (T3) = 24

Common ratio (r) = 2/3

First term (a) =?

24 = a(2/3)²

24 = 4a/9

Cross multiply

24 × 9 = 4a

216 = 4a

Divide both side by 4

a = 216/4

a = 54

Thus, the first term (a) is 54

B. Determination of the sum of the first five terms.

Common ratio (r) = 2/3

First term (a) = 54

Number of term (n) = 5

Sum of first five terms (S5) =?

Sn = a[1 –rⁿ] / 1 – r

S5 = 54[1 – (⅔)⁵] / 1 – ⅔

S5 = 54 [1 – 32/243] / ⅓

S5 = 54 (211/243) × 3

S5 = 54 × 211/81

S5 = 6 × 211/9

S5 = 2 × 211/3

S5 = 422/3

Thus, the sum of the first five terms is 422/3

8 0
3 years ago
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