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ololo11 [35]
2 years ago
8

Pls explain why its a yes pleasee and thx u​

Mathematics
1 answer:
mixas84 [53]2 years ago
3 0
Because -5 is less than or equal to 0
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Write the simplest polynomial function for each set of zeros<br><br> Zeros = -2, 5, -1
deff fn [24]

Answer:

The polynomial is ;

x^3 -2x^2 -13x - 10

Step-by-step explanation:

Given the zeros, we set them to equal zero so as to get the linear factors

Mathematically, that will be as follows;

x = -2

x + 2

x = 5

x-5

x = -1

x + 1

So we have the polynomial as;

(x + 1)(x + 2)(x-5)

= (x -5)(x^2 + 3x + 2)

= x^3+ 3x^2 + 2x -5x^2 -15x - 10

= x^3 -2x^2 -13x - 10

5 0
3 years ago
In a game the player wins if he rolls a 6 on a number cube. If the number cube is rolled 18 times, then what is a reasonable pre
monitta

Answer:

15/18

Step-by-step explanation:

A single di has 6 sides, meaning the probability of rolling a 6 is 1/6. So if you roll a di 18 times you would probably get 6 three times. Meaning the number of unsuccesful rolls would be (18/18 - 3/18). Hope this helps.

8 0
3 years ago
If you were to solve the system using the addition method, what would you multiply the first equation by in order to make the x'
Inessa05 [86]
2 times 2=4
multiply first equation by 2 to get
-4x+6y=12
then add to get

-4x+6y=12
<u>4x-2y=8 +</u>
0x+4y=20

4y=20
y=5

sub back
-2x+3y=6
-2x+3(5)=6
-2x+15=6
-2x=-9
x=9/2=4.5


the number to multiply by is 2
7 0
3 years ago
A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?
Basile [38]

Answer:

B) 2.4 inches

Step-by-step explanation:

The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in <em>one </em>month you need to divide the total by the amount of months. 28.8/12 = 2.4

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
3 years ago
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