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laila [671]
3 years ago
9

Blhvjh gjfgfkytdkykdyrckhg

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

tvubhgfyvug fyicvuui

Step-by-step explanation:

blhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhgblhvjh gjfgfkytdkykdyrckhg

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What is the theoretical probability of the event that a family with two children has one boy and one girl? Make a tree diagram t
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What is the expanded form of this number?<br><br> 18.029
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Step-by-step explanation:

18.029= (1×10)+(8×1)+(2×1100)+(9×1100)

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2 years ago
Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

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2 years ago
In AKLM, m = 86 inches, k = 56 inches and ZL=85°. Find ZM, to the nearest<br> degree.
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Please show a pic so i can understand better
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