Need help with this math question, keep getting the first part correct but the other 2 parts of the function are incorrect. Not
1 answer:
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Answer:
- 22°
Step-by-step explanation:
<em>Refer to picture</em>
Added angles a and b as interior angles of same triangle with angle x to make solving simple.
Angle a is same as 42° since both angles intercept same arc AB.
- a = 42°
Angle b is supplementary with 64° angle as linear pair
- b = 180° - 64° = 116°
Some of the interior angles of a triangle is 180
- x + 42° + 116° = 180°
- x + 158° = 180°
- x = 180° - 158°
- x = 22°
So x times y=15
x+y=12
solve
x+y=12
subtract x from both sides
y=12-x
subsitute
xy=15
x(12-x)=15
distribute
12x-x^2=15
subtract (12x-x^2) from both sides
0=x^2-12x+15
use quadratic formula which is
x=
where you have
0=ax^2+bx+c
so
a=1
b=-12
c=15
subsitute
x=
x=
x=
x=
x=6+/-
x=6+
or 6- 
or aprox
x=10.5826 or 1.41742
the numbers are 10.5826 and 1.41742
x+y=12
solve
x+y=12
subtract x from both sides
y=12-x
subsitute
xy=15
x(12-x)=15
distribute
12x-x^2=15
subtract (12x-x^2) from both sides
0=x^2-12x+15
use quadratic formula which is
x=
where you have
0=ax^2+bx+c
so
a=1
b=-12
c=15
subsitute
x=
x=
x=
x=
x=6+/-
x=6+
x=10.5826 or 1.41742
the numbers are 10.5826 and 1.41742