The length is 7 and the width is 3
Answer:
value of blue dot is -6
Step-by-step explanation:
-6 is visible if you go 3 units to the left of -3. -3 - 3 = -6.
To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"
Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.
Now, we have to recall that:
- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles
- also the sum of all the angles in any triangle is 180 degrees
Now, considering the isosceles triangle OQR, we have that:

Now, since the figure already shows that angle
Now, since we have established that the base angles
we can now solve the above equation for m<2 as follows:

Therefore, the correct answer is: option D
Answer 3,5,7
Step-by-step explanation:
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588