8:00 a.m all the way until 2:00 p.m.
8:00 a.m. to 12:00 p.m is
4 hours.
12:00 p.m. to 2:00 p.m is
2 hours8:00 a.m. to
2:00 p.m. is
6 hours.
6 hours out of a 24 hour day.
The school holds classes for
25% of the 24-hour day.
Answer:
y = 2 - ( x - 1)²/9
Step-by-step explanation: See Annex
As the parameter t increases, the value of x increases and the value of y decreases, we get the figure of the annex ( the arrow in the Annex indicates the way of the curve with t increasing.
b) to eliminate the parameter:
x = 1 + 3*t (1) y = 2 - t² (2)
Then from equation (1) t = ( x - 1 ) / 3
plugging that value in equation (2)
y = 2 - [ ( x - 1 ) / 3 ]²
y = 2 - ( x² + 1 - 2*x)/9
9*y = 18 - x² + 1 - 2*x or y = 2 - ( x - 1)²/9
The curve is a parabol
Answer:
For f(x) = √(2·x + 2) - √(x + 18), at f(x) = -1 the possible x-values includes;
-0.757, -17.5
Step-by-step explanation:
Given that the function is f(x) = √(2·x + 2) - √(x + 18)
The value of 'x' when f(x) = -1, is given as follows;
-1 = √(2·x + 2) - √(x + 18)
-1² = (√(2·x + 2) - √(x + 18))² = 3·x + 20 - 2·√(2·x + 2)×√(x + 18)
1 = 3·x + 20 - 2·√(2·x + 2)×√(x + 18)
2·√(2·x + 2)×√(x + 18) = 3·x + 20 - 1 = 3·x + 19
2·x² + 38·x + 36 = (3·x + 19)/2
2·x² + 38·x + 36 - (3·x + 19)/2 = 0
4·x² + 73·x + 53 = 0
From which we get;
x = (-73 ± √(73² - 4 × 4 × 53))/(2 × 4)
x ≈ -0.757, and x ≈ -17.5
Answer: I would have to say its zero
Sorry if I got it wrong
The answer is A because 1/3 is same as 3,1 (&) the 6 is alone without the 0 cause zero is worth nothing
