2 years ago

Find the sum of the first 150 positive even integers.

Mathematics

1 answer:

Gnoma [55]2 years ago

3 0

Answer:

22650

Step-by-step explanation:

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VMariaS [17]

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Seven-tenths of the product of 5p and 3 in algebraic expression

maw [93]

Answer:

$\frac{7}{10}(5p*3)$

Step-by-step explanation:

we know that

The algebraic expression of seven-tenths is equal to the number 7 divided by ten

$\frac{7}{10}$

The algebraic expression of the product of 5p and 3 is equal to multiply 5p by 3

$(5p*3)$

therefore

The algebraic expression of seven-tenths of the product of 5p and 3 is equal to

$\frac{7}{10}(5p*3)$

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4 years ago

What’s the volume of a cone with the height of 18 and base of 8

sergij07 [2.7K]

Answer:

Step-by-step explanation:

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4 years ago

Consider a particle that moves through the force field F(x, y) = (y − x)i + xyj from the point (0, 0) to the point (0, 1) along

sleet_krkn [62]

The work done by $\vec F$ is

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r$

where $C$ is the given curve and $\vec r(t)$ is the given parameterization of $C$ . We have

$\mathrm d\vec r=\dfrac{\mathrm d\vec r}{\mathrm dt}\mathrm dt=k(1-2t)\,\vec\imath+\vec\jmath$

Then the work done by $\vec F$ is

$\displaystyle\int_0^1((t-kt(1-t))\,\vec\imath+kt^2(1-t)\,\vec\jmath)\cdot(k(1-2t)\,\vec\imath+\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1((k-k^2)t-(k-3k^2)t^2-(k+2k^2)t^3)\,\mathrm dt=-\frac k{12}$

In order for the work to be 1, we need to have $\boxed{k=-12}$ .

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3 years ago

Please help me out please ASAP

ch4aika [34]

Answer:

work it out backwards

264/2 = 132

132 X 100 / 6 = 2200

$2200

7 0

3 years ago