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3 years ago

Identify the maximum of the graph below. Type your answer by filling in the blanks below

Mathematics

1 answer:

nevsk [136]3 years ago

8 0

Answer:

The maximum point of this function is (5,4).

Step-by-step explanation:

The maximum of a function is the maximum value that it can take.

Seeing the graph we can say that the maximum value of y occurs at x = 4. Here y = 5 corresponds to this value of x.

Therefore, the maximum point of this function is (5,4).

I hope it helps you!

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In a class, 45 students are taking the SAT exam.The number of boys is 9 more than the number of girls.How many girls and boys ar

maxonik [38]

The equation would be
g + (g + 9) = 45
2g + 9 = 45
- 9
2g = 36
÷ 2
g = 18
18 + 9 = 27
Girls: 18
Boys: 27
Hope this helps! Let me know if you have any questions :)

7 0

3 years ago

AC=<br> Help me please!! Thanks so much

katovenus [111]

Answer:

AC = 6√3 in

Step-by-step explanation:

<h3>Finding the length of the chord:</h3>

Join OC. Now ΔAOC is an isosceles triangle as OA = OC =radius.

∠A = ∠C = 30.

∠A + ∠C + ∠AOC = 180 {angle sum property of traingle}

30 + 30 + ∠AOC = 180°

∠AOC = 180 -60

∠AOC = Ф = 120°

Find the length of radius using the bellow formula.

$\sf \boxed{\bf Arc \ length = \dfrac{\theta}{180}\pi r}$

Ф = 120°

Arc length = 4π

$\sf 4\pi =\dfrac{120}{180}*\pi *r\\\\ r =\dfrac{4\pi * 180}{120*\pi }\\\\ r = 6 \ in$

$\sf \boxed{\bf chord \ length = 2rSin \ \dfrac{\theta}{2}}$

$\sf b = 2*6*Sin \ \dfrac{120}{2}\\\\ b = 2 *6 * Sin \ 60^\circ\\\\ b = 2 * 6 * \dfrac{\sqrt{3}}{2}\\\\ \b = 6\sqrt{3}$

$\sf \boxed{\bf AC = 6\sqrt{3} \ in}$

5 0

2 years ago

A random sample of 133 people was taken from a very large population. Sixty-five of the people in the sample were females.The st

rjkz [21]

Answer: 0.0433

Step-by-step explanation:

Given: Sample size : n= 133

The number of females in sample = 65

Then the proportion of females : $P=\dfrac{65}{133}$

The formula to calculate the standard error of the proportion is given by :-

$S.E.=\sqrt{\dfrac{P(1-P)}{n}}$

$\Rightarrow S.E.=\sqrt{\dfrac{\dfrac{65}{133}(1-\dfrac{65}{133})}{133}}\\\\\Rightarrow\ \Rightarrow S.E.=0.0433444676341\approx0.0433$

Hence, the standard error of the proportion of females is 0.0433.

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3 years ago

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