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3 years ago

Last year a business had profits of 8,000. This year its profits are 5 times as great. What are this year's profits?

Mathematics

2 answers:

Yanka [14]3 years ago

6 0

The profits are 40,000 i would believe

nignag [31]3 years ago

5 0

This year's profits are 40,000

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Please answer this question Show your work also

DedPeter [7]

Answer:

t = -14

Step-by-step explanation:×

I did 4+3 which equals 7.

Now I know I need t/-2 to equal 7.

Next, I did 7×2 which equals 14.

When you divide 2 negative numbers you get a positive number.

So -14 ÷ -2 = 7

So t = -14

7 0

2 years ago

Read 2 more answers

Name the ordered pair for the point. A

miv72 [106K]

Answer:

point A is (-1.5, 1.5)

Step-by-step explanation:

Hope This Helps!

4 0

2 years ago

a rally car course covers 51 5.97 miles .the winning car completed the course in 6.5 hours. what was the average speed of the wi

Artyom0805 [142]

Assuming the speed is in miles per hour, simply divide the total distance by time.
515.97/6.5
The answer is 79.38 miles per hour

5 0

3 years ago

What problem makes 49

torisob [31]

45 + 4 makes 49 if that counts

6 0

2 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago