4b²+20b+25=0
Divide everything by 4
b²+5b+ 6.25=0
use the quadratic formula
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2
Rule needed: i^2 = -1
Standard form a + bi
(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
3 * - 5i = - 15i
2i * 7 = 14i
2i * -5i = - 10i^2 = - 10 * -1 = 10
Putting it all back together.
31 - i
The opposite angles are equal to are supplementary to each other or equal to each other.
<h3>What is a Quadrilateral Inscribed in a Circle?</h3>
In geometry, a quadrilateral inscribed in a circle, also known as a cyclic quadrilateral or chordal quadrilateral, is a quadrilateral with four vertices on the circumference of a circle. In a quadrilateral inscribed circle, the four sides of the quadrilateral are the chords of the circle.
The opposite angles in a cyclic quadrilateral are supplementary. i.e., the sum of the opposite angles is equal to 180˚.
If e, f, g, and h are the inscribed quadrilateral’s internal angles, then
e + f = 180˚ and g + h = 180˚
by theorem the central angle = 2 x inscribed angle.
∠COD = 2∠CBD
∠COD = 2b
∠COD = 2 ∠CAD
∠COD = 2a
now,
∠COD + reflex ∠COD = 360°
2e + 2f = 360°
2(e + f) =360°
e + f = 180°.
Learn more about this concept here:
brainly.com/question/16611641
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