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2 years ago

Whats the answer for this 4b²+20b+25

1 answer:

7 0

4b²+20b+25=0

Divide everything by 4

b²+5b+ 6.25=0

use the quadratic formula
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2

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Write 0.5 as an integer

arsen [322]

Step-by-step explanation:

"A Whole number is an integer not decimal, fractions and imaginary numbers." -WikiUser.

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3 years ago

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
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8 0

2 years ago

Andrew's math teacher entered the seventh grade students in a math competition there was an enrollment fee of $30 and also an $1

N76 [4]

Answer: 110

Step-by-step explanation:

Given;

Total cost C = $151

Enrollment fee E = $30

Charge per 10 test t = $11

n is the number of packet of test taken.

The questions can be represented by the equation below;

30 + 11n = 151

Substracting 30 from both sides.

11n = 151-30 = 121

n = 121/11

n = 11

Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;

N = 10 n = 10 ×11 = 110

N = 110

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3 years ago

Math help ✄✐

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D) as age increases, weight increases by 5

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2 years ago

Jenna bought 3 pairs of socks that cost $2.00 a pair. She also bought a blouse for $5.98. She gave the cashier $15. How much cha

defon

Answer:

$3.02

Step-by-step explanation:

Jenna bought 3 pairs of socks that costed her $2.00 each.

So, $2.00 times the 3 pairs she bought is $6.00.

Jenna also bought a blouse for $5.98

$6.00 from the 3 pairs of socks she bought and $5.98 from the blouse would equal a total of $11.98

Jenna gave the cashier $15.00

$15.00 minus the total of $11.98 is $3.02

Jenna recieved $3.02 back

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3 years ago