Consider the equation
.
First, you can use the substitution
, then
and equation becomes
. This equation is quadratic, so
.
Then you can factor this equation:
.
Use the made substitution again:
.
You have in each brackets the expression like
that is equal to
. Thus,
![x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=%20x%5E3%2B5%3D%28x%2B%5Csqrt%5B3%5D%7B5%7D%29%28x%5E2-%5Csqrt%5B3%5D%7B5%7Dx%2B%5Csqrt%5B3%5D%7B25%7D%29%20%2C%5C%5Cx%5E3%2B1%3D%28x%2B1%29%28x%5E2-x%2B1%29%20%20%20)
and the equation is
.
Here
and you can sheck whether quadratic trinomials have real roots:
1.
.
2.
.
This means that quadratic trinomials don't have real roots.
Answer:
If you need complex roots, then
.
Answer:
$5
Step-by-step explanation:
Given data
We are given that
Large lemonade= $6
Small lemonade= $4
Total amount = 6+4= $10
He keeps 50% of the total
= 50/100*10
=0.5*10
= $5
Hence he will keep $5
Answer:
none of your options are right
Step-by-step explanation:
<h2>Three less than seven times a number:</h2>
<u><em>three : 3, less than : (-), seven : 7, times : (multiplication symbol), a number : (x)</em></u>
<u><em>the answer is : 3 - 7 (x)</em></u>
<u><em>: 3-7x</em></u>
The complex number is given as: 2-8i
So for conjugate, you just flip the sign of the imaginary part:
2+8i will be the answer