Answer:
1/5
Step-by-step explanation:
subtract 2/3 and 3/5
<span>-10 < x - 9
</span><span>-10+9 < x - 9+9
-1<x, or
x> - 1</span>
∫( (sinx) / (2 - 3cosx)) dx.
From laws of integration: ∫ f¹(u) / f(u) du = In(f(u)) + constant.
d/dx (2 - 3cosx) = 0 -3(-sinx) = 3sinx.
1/3d/dx(2 - 3cosx) = (1/3)*3sinx = sinx.
∫ ((sinx) / (2 - 3cosx)) dx. = ∫ ((1/3) d/dx (2 - 3cosx) / (2 - 3cosx))dx
= 1/3 ∫ (d/dx (2 - 3cosx) / (2 - 3cosx))dx
= (1/3)ln(2 - 3cosx) + Constant.
Add them up and multyply them. :)
hope this helped
152700 is answer. Try to do these problems on paper then you can see where you went wrong . also try to do the actual question
