The simplified radical for the given equation is 2√3.
The given equation is 
.
<h3>What are radicals?</h3>
Radical of any number is the same as the root of the number. The root can be a square root, cube root, or in general, it is nth root. Thus, any expression or number that uses a root is known as a radical.
To compute for the values of x given the proportion, we can cross-multiply both sides of the equation as follows:
⇒x×x=3×4
⇒x²=12
⇒x=±√12
From this, we can see that the solutions for the equation are the positive and negative roots of 12.
By simplifying the radical, we get √12 = √(2² x 3) = 2√3
Therefore, the simplified radical for the given equation is 2√3.
To learn more about radicals visit:
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Infinite solutionsthats what i think it is
Im not exactly sure but i think:
r^2+6r+2
________
5r^2-5r-25
remember IM NOT SO SURE
Step-by-step explanation:
15a)
Subtract both sides by 21
15b)
7 and -3 multiply to -21 and add to 4
The factors are (x+7)(x-3)
15c)
x+7 =0
x=-7
x-3=0
x=3
The answer is diameter: 32 in, area: 64 in²
The perimeter of a sector of a circle is:
P = 2r + l
l = r<span>θ
P = 2r + r</span>θ<span>
P = 32 in
32 = 2r + r</span><span>θ
</span>32 - 2r = r<span>θ
</span>θ = (32 - 2r)/r
θ = (2*16 - 2*r)/r
θ = 2(16 - r)/r<span>
Area of the sector of the circle is:
A = r</span>²/2 * θ
A = r²/2 * 2(16 - r)/r
A = r² * (16 - r)/r
A = r(16 - r)
A = 16r - r²
For the maximum area:
A' = 16 - 2r
A' = 0
16 - 2r = 0
16 = 2r
r = 8 in
The diameter (D) of the circle is twice of the radius:
D = 2r = 2 * 8 = 16 in
The maximum area is:
A = 16r - r²
r = 8 in
A = 16 * 8 - 8²
A = 128 - 64
A = 64 in²
