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2 years ago

Draw a line representing the "rise" and a line representing the "run" of the line. State

Mathematics

1 answer:

steposvetlana [31]2 years ago

4 0

Answer:

The slope should be -2

You should go down 2 and go over 1.

Slope Intercept Form: y= -2x+3

Step-by-step explanation:

First, you need to identify the slope: (meaning whether it is a postive or negative.)

In this case, You have a negative slope.

This means instead of rising you're decreasing down.

When you "run" or move horizontally you MUST move right even if it's a negative slope.

Now, you need to identify your Y-Intercept.

Your Y-Intercept should be (0,3)

Next, you have to find your slope:

In order to find your slope, you need to find where the line is crossing the coordinate.

Start at (-1,5) and go down and over to (0,3)

Your answer should be that you went down 2 and over 1.

The slope can't be 2 because if it were to be 2, then that would be a positive slope which isn't our occasion.

The slope is -2.

In Slope Intercept Form: y= -2x+3

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What is the value of h in the parallelogram

Inga [223]

Answer:Opposite sides are equal in length and opposite angles are equal in measure. To find the area of a parallelogram, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

Step-by-step explanation:

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3 years ago

valina [46]

Answer:

solution e. (0,0)______b. (-2,-10)_______c. (5, -12)__________of

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3 years ago

A right circular cylinder is changing shape. The radius is decreasing at the rate of 2 inches/sec while it's height is increasin

Savatey [412]

Answer:

Step-by-step explanation:

Volume of a cylinder is expressed as;

$V = \pi r^2 h$

$\frac{dV}{dt} = \frac{dV}{dr} \frac{dr}{dt} +\frac{dV}{dh} \frac{dh}{dt}$

dV/dr = 2πrh

dV/dr = 2π(4)(6)

dV/dr = 48(3.14)

dV/dr = 150.72in³/m

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dV/dh = 3.14(4)²

dV/dh = 50.24

Given

dh/dt = 5in/s

dr/dt = 2in/s

Substitute into the dV/dt

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The volume is changing at the rate of 552.640in³/s

7 0

2 years ago

Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x < 0.

sergij07 [2.7K]

(a) If f(x) is to be a proper density function, then its integral over the given support must evaulate to 1:

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx = \int_0^\infty cxe^{-x^2}\,\mathrm dx=1$

For the integral, substitute u = x ² and du = 2x dx. Then as x → 0, u → 0; as x → ∞, u → ∞:

$\displaystyle\frac12\int_0^\infty ce^{-u}\,\mathrm du=\frac c2\left(\lim_{u\to\infty}(-e^{-u})-(-1)\right)=1$

which reduces to

c / 2 (0 + 1) = 1 → c = 2

(b) Find the probability P(1 < X < 3) by integrating the density function over [1, 3] (I'll omit the steps because it's the same process as in (a)):

$\displaystyle\int_1^3 2xe^{-x^2}\,\mathrm dx = \boxed{\frac{e^8-1}{e^9}} \approx 0.3678$

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2 years ago

Need answer ASAP *MARKING BRAINLIEST

Rzqust [24]

Answer:

y=-2/3x +1

Slope = The change in y over the change in x so to do this you can use the two points To find the change in y to be -1-3=4 And the change in x to be 3 -(-3)=6 so you get -4/6 which can be simplified to -2/3 Then to find the next part find the y intercept which is y=1 at x=0

8 0

3 years ago