Answer:
half the diagonal is given as 7 yards, the full diagonal would be 7 x 2 = 14 yards.
The formula for the length of a side of a square using just the diagonal is:
Side = √2(d/2)
Side = √2 (14/2)
Side = √2(7)
Side = 9.9 yards.
The area of a square is S^2
Area = 9.9^2
Area = 98.01
Area = 98.0 Yards^2
Answer:
2
Step-by-step explanation:
rise ove run
3 over 6
Answer:
The number of words in the code in 2035 will be 11.62 million words
Step-by-step explanation:
Let
x -----the number of years since 1955
y ----> the number of words in some code in millions
![2005-1955=50\ years](https://tex.z-dn.net/?f=2005-1955%3D50%5C%20years)
we have the points
(0,1.7) and (50,7.9)
<em>Find the slope m</em>
![m=(7.9-1.7)/(50-0)\\m=6.2/50\\m=0.124](https://tex.z-dn.net/?f=m%3D%287.9-1.7%29%2F%2850-0%29%5C%5Cm%3D6.2%2F50%5C%5Cm%3D0.124)
<em>Find the equation of the line in slope intercept form</em>
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
we have
![m=0.124\\b=1.7](https://tex.z-dn.net/?f=m%3D0.124%5C%5Cb%3D1.7)
substitute
![y=0.124x+1.7](https://tex.z-dn.net/?f=y%3D0.124x%2B1.7)
Predict the number of words in the code in 2035
![x=2035-1955=80\ years](https://tex.z-dn.net/?f=x%3D2035-1955%3D80%5C%20years)
substitute in the equation
![y=0.124(80)+1.7](https://tex.z-dn.net/?f=y%3D0.124%2880%29%2B1.7)
![y=11.62](https://tex.z-dn.net/?f=y%3D11.62)
therefore
The number of words in the code in 2035 will be 11.62 million words