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Dmitrij [34]
2 years ago
5

A quadrilateral can be partitioned into two triangles. What is the sum of the angles of a quadrilateral?​

Mathematics
1 answer:
Dimas [21]2 years ago
8 0

Answer:

360°

Step-by-step explanation:

Each of the two triangles have 3 angles that add up to 180°.

So,

180° + 180° = 360°

The sum of the angles of a quadrilateral is 360°

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dg

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207

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3 is a factor of__ A)282 B)187 C)385 D)412​
MrRissso [65]

Answer:

A. 282

Step-by-step explanation:

A trick I know is if you add all the digits of the number and they add up to a multiple of 3, it is divisible by 3.

282:

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187:

1 + 8 + 7 = 16

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3 + 8 + 5 = 16

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3 years ago
Read 2 more answers
Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
3 years ago
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