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3 years ago

Please help me on 1,2, and 3 please help

Mathematics

1 answer:

mart [117]3 years ago

5 0

Answer: put it in rice<333

Step-by-step explanation:

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3x-5=-8(6+5x) plz help me with this problem

ArbitrLikvidat [17]

Answer:

X=-1

Step-by-step explanation:

3x-5=-8(6+5x)

3x-5=-48-40x

43=-43x

-1=x

5 0

4 years ago

Suppose that A and B are square matrices and that ABC is invertible. Show that each of A, B, and C is invertible.

Dimas [21]

Answer:

Step-by-step explanation:

Let A, B and C be square matrices, let $D = ABC$ . Suppose also that D is an invertible square matrix. Since D is an invertible matrix, then $det (D) \neq 0$ . Now, $det (D) = det (ABC) = det (A) det (B) det (C) \neq 0$ . Therefore,

$det (A) \neq 0$

$det (B) \neq 0$

$det (C) \neq 0$

which proves that A, B and C are invertible square matrices.

8 0

4 years ago

The parabola with the vertex at (5,5) and a focus (7,5) would open

muminat

Answer:

Up. The focus is above the vertex meaning the parabola will open up. If the focus was below the parabola then it would open down.

Step-by-step explanation:

6 0

3 years ago

Given: ABCD is a trapezoid, AB= 13, CD = 14, BC = 5, and AD= 20. Find: A ABCD

Romashka [77]

Answer:

A=13×13

=169sqr.units

7 0

3 years ago

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v

Svetllana [295]

Answer:

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by $\frac{dV}{dt}$

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒ $\frac{dV}{dt}$ ∝ $\sqrt[3]{V}$

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

6 0

3 years ago