HELP!! I only have one more try to get this problem correct.

The slope of the line that passes through the points on the graph of the function is

trasher [3.6K]

I do believe that this answer will Slope intercept

3 0

3 years ago

Mark, Carlos, Ben, and Taj ran the 1,600-meter relay today at the track meet. If their times were 55.2 seconds, 54.34 seconds, 5

ad-work [718]

55.2+54.34+55.16+52.08 = 216.77
So A

4 0

3 years ago

Read 2 more answers

Drag each interval to a box to show if the function shown is increasing, decreasing, or neither over that interval.

ad-work [718]

Answer:

First, we need to know when the function is increasing, and when is decreasing.

When a function is increasing, it's because to higher x-values belong higher y-values. On the other hand, a function is decreasing when to higher x-values belong lower y-values. The effect in the graph will be a upwards direction of the function when is increasing, and a downwards direction when is decreasing.

So, according to the given graph, we see that between 0 and 4 is increasing, the higher x-values are, higher y-values are. Between 4 and 6 is decreasing, is downwards. Between 6 and 8 is increasing. Between 8 and 10 is decreasing. In finally, between 10 and 14 is neither decreasing or increasing, it remains horizontal.

All these interpretations we can expressed using math language, specifically inequalities:

0 < x < 4: increasing.
4 < x < 6: decreasing.
6 < x < 8: increasing.
8 < x < 10: decreasing.
10 < x < 14: neither increasing or decreasing.

4 0

4 years ago

What is the equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y =

Zepler [3.9K]

The equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y = 3 in standard form is x - 2y = - 3

Solution:

Given, line equation is 2x + y = 3

2x + y – 3 = 0 ----- eqn (1)

We have to find a line that is perpendicular to 2x + y – 3 = 0 and passing through (5, 4).

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{1}=-2$

$\text { Slope of a line } \times \text { slope of perpendicular line }=-1$

$\begin{array}{l}{-2 \times \text { slope of perpendicular line }=-1} \\\\ {\text { Slope of perpendicular line }=-1 \times \frac{1}{-2}=\frac{1}{2}}\end{array}$