Question

Could someone please help me really quickly?

Answer 1

$6x^2 +17x -3\\\\=6x^2 +18x-x-3\\ \\=6x(x+3)-(x+3)\\ \\=(x+3)(6x-1)\\\\\text{The length and width of the rectangle are}~ (6x-1)~ \text{and}~ (x+3)$

Answer 2

Answer:

$\textsf{length}=6x - 1$

$\textsf{width}=x+3$

Step-by-step explanation:

Area of a rectangle = length × width

Given area:  $A=6x^2+17x-3$

Therefore,  $6x^2+17x-3=\sf length \cdot width$

To find the length and width, we need to factorize the given expression for area.

To factor a quadratic in the form $ax^2+bx+c$

• Find 2 two numbers (d and e) that multiply to ac and sum to b
• Rewrite b as the sum of these 2 numbers: d + e = b
• Factorize the first two terms and the last two terms separately, then factor out the comment term.

$6x^2+17x-3 \implies a=6, b=17, c=-3$

$ac=6 \cdot -3=-18$

$d+e=17$

So we are looking for a pair of numbers that multiply to -18 and sum to 17.

Factors of 18: 1, 2, 3, 6, 9, 18

Therefore, the two numbers (d and e) that multiply to -18 and sum to 17 are:

18 and -1

Rewrite $17x$ as $+18x-x$:

$\implies 6x^2+18x-x-3$

Factor first two terms and last two terms separately:

$\implies 6x(x+3)-1(x+3)$

Factor out common term $(x+3)$:

$\implies (6x-1)(x+3)$

As length > width,

$\textsf{length}=6x - 1$

$\textsf{width}=x+3$