A construction compony purchased 24 boxes of nails. Each box cost $87. How much did the nails cost the construction company?

The sum of three consecutive integers is 33. Find the numbers.

Rufina [12.5K]

Answer:

A

Step-by-step explanation:

x+x+1+x+2=33

3x+3=33

3x=30

x=10

so x+1 =11

x+2 =12

5 0

4 years ago

HELP ME PLZ I NEED HELP BAD

ElenaW [278]

Answer:

mode: 2

median: 3

range is 9

6 0

3 years ago

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What is the surface area of the rectangular prism below?<br> With sides 8 ,8 , 19

Lyrx [107]

Answer:

736

Step-by-step explanation:

(2*(8*8))+(2*(8*19))+(2*(19*8))=A

7 0

3 years ago

6. You are given a sheet of cardboard that is 8.0 in. x 11.0 in. How many full circles with a diameter of 3.0 inches can you cut

larisa86 [58]

In order to answer this, it would be useful to calculate the area of the cardboard and the circles. We do as follows:

Total area of cardboard = <span> 8.0 in. x 11.0 in = 88 in^2

Area of one circle = pi(r^2) = pi(0.5)^2 = 0.7854 in^2

Number of full circles = 88 / 0.7854 = 112.0451

Therefore, there will be 112 number of full circles. The percentage of waste is equal to:

% waste = (88 - 0.7854(112) / 88) x 100= 0.04%</span>

4 0

4 years ago

PLEASE HELP.

OverLord2011 [107]

Answer:

Explicit formula for

1) $a_n=17-3(n-1)$

2) $a_n=(\frac{1}{2} )^{n-1}\cdot 20$

Step-by-step explanation:

W have to find the first few terms of the given sequence and then find an explicit equation

Explicit formula = f(n) + d(n-1) , where,

f(n) is first term,

d is common difference,

n-1 is one term less than the term number.

1)

Given : $a_1=17\\\\a_{n+1}=a_n-3$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

2)

Given : $a_1=20\\\\a_{n+1}=\frac{1}{2} \cdot a_n$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

$\text{We put n =1, we get,}\\\\\\a_2=\frac{1}{2} \cdot a_1=\frac{1}{2} \cdot 20=10=(\frac{1}{2} )^{2-1}\cdot 20\\\\\\\text{We put n =3, we get,}\\\\\\a_4=\frac{1}{2} \cdot a_3=\frac{1}{2} \cdot 5=\frac{5}{2}=(\frac{1}{2} )^{4-1}\cdot 20\\\\\\$

Thus, we obtained an explicit formula,

$a_n=(\frac{1}{2} )^{n-1}\cdot 20$

8 0

3 years ago

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