Answer:
yes the answer is A .Step-by-step explanation: because 2x^2 is your a term and -5x is your b term and 18 is your c term and the quadratic formula is -b plus or minus the square root of b squared subtract 4ac all over 2a
Not 100% sure but I think it’s 7
U should get Cymath for math and Socratic for everything they help a lot
We are given two points of a line
(-2, -2) and (1,4)
Equation of line:
Firstly , we will find slope
(-2, -2) and (1,4)
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%20m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%20%20)
![m=\frac{4+2}{1+2}](https://tex.z-dn.net/?f=%20m%3D%5Cfrac%7B4%2B2%7D%7B1%2B2%7D%20%20)
![m=2](https://tex.z-dn.net/?f=%20m%3D2%20%20)
now, we can find equation of line
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=%20y-y_1%3Dm%28x-x_1%29%20%20)
now, we can plug values
and we get
![y+2=2(x+2)](https://tex.z-dn.net/?f=%20y%2B2%3D2%28x%2B2%29%20%20)
![2x-y+2=0](https://tex.z-dn.net/?f=%202x-y%2B2%3D0%20%20)
Distance:
now, we can use distance formula
![d=\frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}](https://tex.z-dn.net/?f=%20d%3D%5Cfrac%7B%7Cax_0%2Bby_0%2Bc%7C%7D%7B%5Csqrt%7Ba%5E2%2Bb%5E2%7D%7D%20%20%20)
firstly , we will find a and b
a=2 and b=-1
point is (6,-1)
so, xo=6 and yo=-1
we can plug values
and we get
![d=\frac{|2*6-1*-1+2|}{\sqrt{(2)^2+(-1)^2}}](https://tex.z-dn.net/?f=%20d%3D%5Cfrac%7B%7C2%2A6-1%2A-1%2B2%7C%7D%7B%5Csqrt%7B%282%29%5E2%2B%28-1%29%5E2%7D%7D%20%20%20)
![d=\frac{15}{\sqrt{5}}](https://tex.z-dn.net/?f=%20d%3D%5Cfrac%7B15%7D%7B%5Csqrt%7B5%7D%7D%20%20%20)
...........Answer