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fenix001 [56]
2 years ago
13

A tax that is collected by a company based on sales of products or services

Mathematics
1 answer:
Darya [45]2 years ago
6 0
A Jew on juice and H
You might be interested in
Four Questions, 60 points & Brainliest! (Please show all steps)
pogonyaev

Answer:

a) -2, 1 and 2

b) 4

Step-by-step explanation:

The given equation is:

g(x) = (x + 2)(x - 1)(x - 2)

Part a1 and a2) Finding zeros of the function

By zeroes of the function we mean the points the graph where the value of the function is zero. In order to find the zeroes of the function we equate the  function equation to zero and find the corresponding values of x. This is shown below:

0 = (x + 2)(x - 1)(x - 2)

According to the zero product property, we can write:

x + 2 = 0     ⇒     x = -2

x - 1 = 0      ⇒     x = 1

x - 2 = 0     ⇒     x = 2

Therefore, the zeroes of the given function are -2, 1 and 2. In ordered pairs we can write these as (-2, 0), (1, 0) and (2, 0)

Part b1 and b2) y-intercept of the function

y-intercept is the point on the graph where the function crosses the y-axis. Since on y-axis, the value of x coordinate is zero, in order to find the y-intercept we simply substitute zero for all occurrences of x. This is shown below:

g(0) = (0 + 2)(0 - 1)(0 - 2)

g(0) = 2(-1)(-2)

g(0) = 4

Thus, the y-intercept of the function is 4, which in ordered pair can be written as (0, 4)

Part c) End behavior of the graph

End behavior of the graph depends on:

  • Sign of the leading coefficient
  • Degree of the function

Degree of the function is 3 i.e. odd and sign of leading coefficient is positive. This means the end behavior of the graph will be:

  • Rising towards Right end
  • Falling towards Left end

Part d) Graph of polynomial

Based on all the above discussion, a graph of the function can be plotted. The graph is attached below.

4 0
3 years ago
Mean absolute deviation of 290
Levart [38]

Answer:

3.5555555555556

Step-by-step explanation:

you cannot find the Mean Absolute Deviation of one number. This answer is the data set 2, 9, and 0. 3.5555555555556 is the Mean Absolute Deviation of 2, 9, 0.

7 0
2 years ago
What is <img src="https://tex.z-dn.net/?f=15%5E%7B2%7D" id="TexFormula1" title="15^{2}" alt="15^{2}" align="absmiddle" class="la
umka21 [38]

Amayo943,

Remember that with exponents you have to multiply the number of exponets by the same number it's in for example: 1^2 = 1 \times 1 In this case you need to know that:

  • 15^2 = 15 \times 15
  • 15 \times 15 = 225
  • =225

Therefore your answer is "225."

Hope this helps!

5 0
3 years ago
Need answer asap. will give thanks
kompoz [17]
The answer of the larger circle = 254.34
Formula = radius*radius*π

The answer of the smaller circle = 113.04

254.34 - 113.04 = 141.3

Hope this helped☺☺
4 0
3 years ago
Read 2 more answers
I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
4 years ago
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