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Marrrta [24]
4 years ago
13

Find the number of pairs (a,b) of integers such that a+2/a+5=b/3

Mathematics
1 answer:
Viktor [21]4 years ago
3 0

Answer:

  6

Step-by-step explanation:

The expression can be rearranged to ...

  b = 3 -9/(a+5)

In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.

The attached table shows the values (a, b) = (x₁, f(x₁)).

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Answer:

0(2/3; 0)

Step-by-step explanation:

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Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

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3 years ago
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About 400 marbles. You simply set up a proportion and solve it as I did in the photo attached.

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Answer: look at the picture

Step-by-step explanation: Hope this help :D

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Your averages and values are the following:
ioda

Answer: You need a grade of 78 on the final exam to earn a final grade average of at least 87 in each grading system.

Step-by-step explanation:

(85 + 90 + 95 + x)÷ 4 =87

Simplify:

(270 + x) ÷ 4 = 87

Rearrange:

(x + 270) ÷ 4 = 87

Multiply terms to Reduce:

4((x + 270) ÷ 4) = 4 * 87

Cancel Multiplied terms in Denominator:

x + 270 = 4 * 87

Multiply:

x + 270 = 348

Subtract 270 on both sides of the equation:

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