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solong [7]
2 years ago
9

if the area of a rectangle is represented by the expression 12x^2-5x-3 and the length is 4x-3, what expression represents the wi

dth​

Mathematics
1 answer:
Arturiano [62]2 years ago
8 0

Answer:

option C

Step-by-step explanation:

area of rectangle = length * width

12x^2 - 5x - 3 = (4x - 3) * width

12x^2 - 9x + 4x - 3 = (4x - 3)* width

3x(4x - 3) + 1(4x - 3) = (4x - 3)*width

(3x + 1)(4x - 3) / (4x - 3) = width

3x + 1 = width

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2/11 is 0.181818 as a decimal so closest to 0.

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3 years ago
What is the answer ?
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Analyze the graph of the cube root function shown
Greeley [361]

The values of a, h, and k in the general equation is h=1, k=4 and a=2

<h3>What is parent function?</h3>

The function which can be transformed into different ways is the parent function.

On a coordinate plane, a cubic function approaches the x-axis in quadrant 2, crosses the y-axis at (0, 2), has an inflection point at (1, 4), and the goes through (2, 6).

The given function is

y =a³ √(x -h) + k

Put the coordinate (0,2) in the equation, we get

2 = a³ √(0 -h) + k..................(1)

Plug (1, 4), we have

4 =  a³ √(1 -h) + k..................(2)

Plug (2, 6), we have

6 =  a³ √(2 -h) + k..................(3)

On solving these three equations, we have

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Learn more about parent function

brainly.com/question/17939507

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7 0
2 years ago
An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline
vivado [14]

Answer:

The answer to the question is;

The probability that a seat will be available for every person holding a reservation and planning to fly is 0.63307.

Step-by-step explanation:

Let the sample size =n = 100

The success probability = 5 % = 0.05

Number of tickets sold = 105 tickets

In the case where there the airline has found that 5 % will not show up, then every passenger should have  a seat, we have  

A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 =  5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

 z = \frac{x-np}{\sqrt{np(1-p)}  } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} } =  - 0.3358

We therefore have P(x ≥ 5) = P( x > 4.5) = P(z > -0.34) = 1 - P(z < -0.34) = 1 -0.36693 = 0.63307

Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = \sqrt{npq} = 2.233

P (x≤100) = P(z = P(z<0.34) = 0.63307.

6 0
3 years ago
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