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makkiz [27]
3 years ago
8

You buy a deluxe box of 45 ornaments for your tree for $15 when you get home and open the box you realize that 10 of the ornamen

ts are broken how much money did you waste and how much money did each ornament cost
Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

$ wasted: 3.33, Each Ornament Cost: $0.33

Step-by-step explanation:

45 ornaments cost $15

Divide both by three

3 ornaments cost $1

If 10 ornaments are wasted, then multiply 1 by 10/3, which equals 3.33.

Since 3 ornaments cost $1, divide 1 by 3 to get 0.33

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A sign company charges $28 per yard for each custom made banner. Ms. Gill orders two banners that are each 1 7/8 yards yards lon
Svetlanka [38]

Answer:

$896

Step-by-step explanation:

We are given that

Charge of 1 yard for each custom-made banner=$28

Length of 1 piece=15 yards

Length of another piece=2 yards

We have to find that how much money payed by Ms.Gill for all three banners.

According to question

Cost of 15 yards long banner=$420

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Cost of 2 yards long banner==$56

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Your Welcome;)

8 0
3 years ago
Can someone help me out plz
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3 years ago
Are you getting enough sleep? Many kids aren’t getting enough sleep, and TV might be part of the problem. Among 2002 randomly se
Naya [18.7K]

Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:

d. 68.39%.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so the critical value is z = 2.575.

The sample size and estimate are given by:

n = 2002, \pi = 0.71

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\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.71 - 2.575\sqrt{\frac{0.71(0.29)}{2002}} = 0.6839

Hence the lower bound is of 68.39%, which means that option D is correct.

More can be learned about the z-distribution at brainly.com/question/25890103

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