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1 year ago

Find the solution of the system of equations. x-y=-3-8x+y=45

Mathematics

1 answer:

mezya [45]1 year ago

5 0

Answer:

x = 17, y = 28

Step-by-step explanation:

1. Isolate for x in "x - y = -3, -8":

x - y+y = -3, -8+y

x = -11 + y

2. Substitute "x = -11 + y" in for x in the second expression:

-11 + y + y = 45

3. Simplify:

-11 + 2y = 45

4. Isolate y:

-11+11 +2y = 45+11

2y = 56

$\frac{2y}{2} = \frac{56}{2}$

y = 28

5. Substitute the new y-value into the first equation:

x = -11 + 28

x = 17

hope this helps!

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umka2103 [35]

Answer:

The short answer is : x=6.81

Step-by-step explanation:

First thing to do is multiply in $\sqrt{2}$

<h3>To Until it become :</h3>

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Now we will divided on 5 and calculate the numper to it equal 46.3

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To equal in the end =6.81

6 0

3 years ago

15 POINTS!!! HELP ASAP!! What are the domain and range of the function graphed below?

aleksklad [387]

Answer:

C. domain: {x ≤ 2}; range: {–∞ < y < ∞}

that's the right answer pramis:)

8 0

3 years ago

Read 2 more answers

(−5)3x7(yz)4 / (3)2x2y8z2

g100num [7]

Answer:

$\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}$

Step-by-step explanation:

Given:

The expression to simplify is given as:

$\frac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}$

In order to simplify this, we have to use the law of indices.

1. $(ab)^m=a^mb^m$

So, $(yz)^4=y^4z^4$

Substitute this value in the above expression. This gives,

$=\dfrac{(-5)3x^7y^4z^4}{(3)2x^2y^8z^2}\\\\\\=\dfrac{-15x^7y^4z^4}{6x^2y^8z^2}......(-5\times 3=15\ and\ 3\times 2=6)$

Now, we use another law of indices.

2. $\frac{a^m}{a^n}=a^{m-n}$

So, $\frac{x^7}{x^2}=x^{7-2}=x^5,\frac{y^4}{y^8}=y^{4-8}=y^{-4}, \frac{z^4}{z^2}=z^{4-2}=z^2$

Substitute these values in the above expression. This gives,

$=\frac{-15}{6}\times x^5\times y^{-4}\times z^2\\\\=\frac{-5x^5y^{-4}z^2}{2}$

Finally, we further simplify it using the law $a^{-m}=\frac{1}{a^m}$

So, $y^{-4}=\frac{1}{y^4}$

Therefore, the given expression is simplified as:

$\dfrac{(-5)3x^7(yz)^4}{(3)2x^2y^8z^2}=\dfrac{-5x^5z^2}{2y^4}$

5 0

3 years ago

A=12 B=5 C=2 if you help your maked as the brainest

Afina-wow [57]

C^2+(2/3)
2^2+(2/3)
4+(2/3)
4 2/3

Final answer: 4 2/3 or 14/3 as an improper fraction

6 0

3 years ago

Read 2 more answers

Use partial quotients to solve 504 divide 14

miv72 [106K]

Answer:

Perform the following division using partial quotients: 504 ÷ 14:

To reduce the numerator, we will be multiplying the denominator by factors of 10, 5, 2, and 1

Step-by-step explanation:

1 4| 5 0 4

2 8 0 20 <---- 20 x 14 = 280

2 2 4 <---- 504 - 280 = 224

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10 <---- 10 x 14 = 140

8 4 <---- 224 - 140 = 84

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5 <---- 5 x 14 = 70

1 4 <---- 84 - 70 = 14

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5

1 4

1 4 1 <---- 1 x 14 = 14

0 <---- 14 - 14 = 0

Our partial quotients add up as follows:

20 + 10 + 5 + 1 = 36

I hope it helps plz Mark me brainliest:)

5 0

3 years ago