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abruzzese [7]
1 year ago
11

Find the solution of the system of equations. x-y=-3-8x+y=45

Mathematics
1 answer:
mezya [45]1 year ago
5 0

Answer:

x = 17, y = 28

Step-by-step explanation:

1. Isolate for x in "x - y = -3, -8":

x - y+y = -3, -8+y

x = -11 + y

2. Substitute "x = -11 + y" in for x in the second expression:

-11 + y + y = 45

3. Simplify:

-11 + 2y = 45

4. Isolate y:

-11+11 +2y = 45+11

2y = 56

\frac{2y}{2} = \frac{56}{2}

y = 28

5. Substitute the new y-value into the first equation:

x = -11 + 28

x = 17

hope this helps!

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Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to save £80?

5 weeks

7 0
3 years ago
HELP ME PLEASE ASAP
sleet_krkn [62]

D :- 10 - 25 = -5

4 - 5 = -1

Required Answer:- -1

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19. (9+2) X 6 -5=<br> Help
Nata [24]

Answer:

61

Step-by-step explanation:

Use PEMDAS (Parenthesis first, Exponents second, Division/Multiplication third, Addition/Subtraction last)

(9+2) x 6 - 5

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61

6 0
3 years ago
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PLEASE HELP!!!!
wel

Answer:

Mike is not right

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the enlarged rectangular prism

y-----> surface area of the original rectangular prism

z^{2}=\frac{x}{y}

so

In this problem we have

z=2

substitute

2^{2}=\frac{x}{y}

4=\frac{x}{y}

x=4y

so

The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism

therefore

Mike is not right

<em>Verify with an example</em>

we have a rectangular prism

L=5\ m

W=2\ m

H=3\ m

The surface area of the prism is equal to

SA=2(LW)+(2L+2W)H

substitute the values

SA=2*(5*2)+(2*5+2*2)*3=62\ m^{2}

If he doubles each dimension of any rectangular prism

then

the new dimensions will be

L=5*2=10\ m

W=2*2=4\ m

H=3*2=6\ m

The new surface area will be

SA=2*(10*4)+(2*10+2*4)*6=248\ m^{2}

248/62=4

therefore

The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism

8 0
3 years ago
All you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd
Brut [27]

We have the following:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}

replacing:

\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}

6 0
1 year ago
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