TEN POINTS

1. If m varies directly as v2 and m = 3, when v =2, calculate the value of m when v =9.<br> (3marks)

Salsk061 [2.6K]

Answer:

3 0

3 years ago

Blake is playing a racing game on his computer. The game tracks the locations of objects using and y coordinates (see graph belo

Anvisha [2.4K]

<h3>Answer: 2.2 units</h3>

============================================

Explanation:

I'll define these point labels

B = Blake's starting position
F = finish line
C = the third unmarked point of the triangle

The locations of the points are

B = (-8,1)
C = (-6,-3)
F = (4,-2)

Use the distance formula to find the distance from B to C

$B = (x_1,y_1) = (-8,1) \text{ and } C = (x_2,y_2) = (-6,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-8-(-6))^2 + (1-(-3))^2}\\\\d = \sqrt{(-8+6)^2 + (1+3)^2}\\\\d = \sqrt{(-2)^2 + (4)^2}\\\\d = \sqrt{4 + 16}\\\\d = \sqrt{20} \ \text{ ... exact distance}\\\\d \approx 4.47214 \ \ \text{... approximate distance}\\\\$

Segment BC is roughly 4.47214 units long.

Following similar steps, you should find that segment CF is approximately 10.04988 units long.

If Blake doesn't take the shortcut, then he travels approximately BC+CF = 4.47214+10.04988 = 14.52202 units. This is the path from B to C to F in that order.

---------

Use the distance formula again to find the distance from B to F. This distance is about 12.36932 units. He travels this amount if he takes the shortcut.

Subtract this and the previous result we got

14.52202 - 12.36932 = 2.1527

That rounds to 2.2

This is the amount of distance he doesn't have to travel when he takes the shortcut.

In other words, the track is roughly 2.2 units shorter when taking the shortcut.

Side note: Replace "units" with whatever units you're working with (eg: feet or meters).

7 0

3 years ago

Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gen

Aleksandr-060686 [28]

Let X be the number of boys in n selected births. Let p be the probability of getting baby boy on selected birth.

Here n=10. Also the male and female births are equally likely it means chance of baby boy or girl is 1/2

P(Boy) = P(girl) =0.5

p =0.5

From given information we have n =10 fixed number of trials, p is probability of success which is constant for each trial . And each trial is independent of each other.

So X follows Binomial distribution with n=10 and p=0.5

The probability function of Binomial distribution for k number of success, x=k is given as

P(X=k) = $(10Ck) 0.5^{k} (1-0.5)^{10-k}$