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2 years ago

QUESTION WORTH 20 POINTS!!! HELP ASAP PLEASE why am i alive

Mathematics

2 answers:

kolezko [41]2 years ago

8 0

If the question is why am I alive, I will answer it.

Although i am not a Christian(I deeply respect those who are, though),

I still believe there is an unnatural force that

selected you to be born and experience life for yourself.

If you are thinking about killing yourself, please call 800-273-8255

guajiro [1.7K]2 years ago

4 0

Answer:

Cause you were born, as simple as that. Plenty of people deal with harsh life.

Step-by-step explanation:

That's not a math question BUT

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O MODULE 1: EXPRESSIONS AND EQUATIONS

Whitepunk [10]

Answer:

First, multiply the 5 by each of the terms inside the parentheses. Next, simplify each part of the expression and then add. The answer is 5(2+3)=25. The distributive property also works if there is subtraction inside the parentheses

Step-by-step explanation:

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3 years ago

49 is 200% of what number

finlep [7]

Idk howbto help u it could be 67 for all i know

4 0

3 years ago

Sally is planning the school picnic and needs to decide what food vendor to use. She asks 250 students whether they would rather

Oksana_A [137]

Answer:

0.18

Step-by-step explanation:

The relative frequency of eight graders who want fruit smoothie :

Number of eight graders who want fruit smoothie / total number of students surveyed

= 45 / 250

= 0.18

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2 years ago

What are compatible numbers?

castortr0y [4]

Compatible numbers are numbers that are close in value to the actual numbers and easy to add, subtract, multiply, or divide mentally. They are useful in estimating the sum, difference, product, or quotient.

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3 years ago

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago