Answer:
Step-by-step explanation:
Hello,
a and b are the zeros, we can say that
So we can say that
Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write
and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes
multiply by 3
Unit cost of a ticket = Income from ticket sales / number of tickets sold:
$1250
--------------- = $6.58 per ticket
190 tickets
Again:
$1175
--------------- = $6.71
175 tickets
While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.
Don't have any guidelines by which to determine the "fixed cost of a ticket".
If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.
Answer:
Step-by-step explanation:
What’s the question?
Answer:
Here you go !!
Step-by-step explanation:
Answer:
As the wheel makes this 270 degree counterclockwise rotation about the origin, the y-coordinate of the first car decreases from 80 to 0 and then further from 0 to -80, and finally increases to 0.
The x-coordinate decreases from 0 to -80 and then increases to 0; from there it increases further to 80.
Thus, the coordinates of the first car, after this 270-degree rotation, are (80, 0).
