If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
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Answer:
Step-by-step explanation:
Given the definite integral 
, we to evaluate it. Using integration by substitution method.
Let u = 1-2x⁵ ...1
du/dx = -10x⁴
dx = du/-10x⁴.... 2
Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;
![= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%5Cdfrac%7Bdu%7D%7Bu%5E5%7D%20%7D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%7Bu%5E%7B-5%7Ddu%20%7D%20%20%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5B%7B%5Cfrac%7Bu%5E%7B-5%2B1%7D%7D%7B-5%2B1%7D%5D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%28%7B%5Cfrac%7Bu%5E%7B-4%7D%7D%7B-4%7D%29%5C%5C%5C%5C)
substitute u = 1-2x⁵ into the result
Hence
The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
Answer:
74 eggs are left
Step-by-step explanation:
91-17=74
Answer:
character vs nature.
minor
I got it right on edge 2021
