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Yuki888 [10]
3 years ago
12

True or False: If lim x → a f(x) does not exist, then f is undefined at the point x = a.

Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

this is absolutely false.

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Andreas93 [3]

Answer:

b = -5/2

Step-by-step explanation:

- 6 (b + 3)= - 8 + 5

- 6b - 18= - 3

- 6b= - 3 + 18

- 6b= 15

b= - 15/6

b= - 5/2

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3 years ago
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A plane flies 510 kilometers with a bearing of 316° from Naples to Elgin (see figure). The plane then flies 720 kilometers from
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What is a radius of a circle given by the equation x²-2x+8y-47=0
Zolol [24]
First, we are going to rewrite it as a parabola equation.
Rewrite.
8y=-x^2+2x+47
Divide by 8.
y=-\frac{x^2}{8}+\frac{x}{4}+\frac{47}{8}
Factor out coefficient.
y=-\frac{1}{8}\left(x^2-2x\right)+\frac{47}{8}
Then, we are going to convert x into square form.
y=-\frac{1}{8}\left(x^2-2x+1\right)+\frac{1}{8}\cdot \:1+\frac{47}{8}
Convert the whole expression into square form.
y=-\frac{1}{8}\left(x-1\right)^2+\frac{1}{8}\cdot \:1+\frac{47}{8}
Simplify.
y=-\frac{1}{8}\left(x-1\right)^2+6
Subtract 6 from both sides.
y-6=-\frac{1}{8}\left(x-1\right)^2
Divide by coefficient.
-8\left(y-6\right)=\left(x-1\right)^2
Rewrite in standard form.
4\left(-2\right)\left(y-6\right)=\left(x-1\right)^2

The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive. 
Have a nice day! :)
7 0
3 years ago
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