Question

Suppose a jar contains 14 red marbles and 31 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red. Answer should be in fractional form.

Answer 1

Answer:

P = 91/990

Step-by-step explanation:

first red marble:    $\frac{14}{45}$

second red marble: $\frac{13}{44}$

The probability

$P=(\frac{14}{45})(\frac{13}{44} )=\frac{(14)(13)}{(45)(44)} =\frac{182}{1980} =\frac{91}{990}$

Hope this helps