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kvv77 [185]
3 years ago
13

Create an equivalent system of equations using the sum of the system and the first equation. −5x + 4y = 8 4x + y = 2

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
8 0
Is the 8 and 4 suppose to be together or ?
brilliants [131]3 years ago
3 0

Answer:

−5x + 4y = 8

−x + 5y = 10

Step-by-step explanation:

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The answer is 100 if that 5 and 2 is separate
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Addy has 51.79 pounds of dirt. She has buckets in her garage. Each bucket can hold 2.5 pounds of dirt. If she has 20 buckets wil
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Answer:

No

Step-by-step explanation:

20x2.5=50

51.79-50=1.79

therefore there isn't enough buckets for all the dirt.

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How many 3/4 pound bags of sugar can be filled with 36 lb of sugar?​
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Answer:

48 bags

Step-by-step explanation:

6 0
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Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ
gulaghasi [49]

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf =  {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf  = 30184 / 1241

Δf  = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41  

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

6 0
3 years ago
a card is chosen from a standard deck, then a month of the year is chosen. find the probability of getting a face card and june​
Irina-Kira [14]

Answer:

Probability of chossing a face card and the month of june = 0.019

Step-by-step explanation:

Let A be the event that a face card is chosen from a deck of 52 cards

And

B be the event that a month is being chosen from 12 months of an year

So,

n(S)for A=52

n(S)for B=12

As a deck of card has total of 12 face cards so

P(A)=12/52

=3/13

P(B)=1/12

As both the events are independent, the probability of A and B is the product of both events’ probabilities.

P(A and B)= P(A)*P(B)

=3/13*1/12

=3/156

=0.019

4 0
3 years ago
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