Answer:
A glucose level between 70 to 105 mg/dL
Explanation:
Casting rope is the answer
Answer
3.5 ml volume of water will be required for sterilization of 700 mg Kanamycin
Explanation
First convert mg to gram
700 mg = 0.7 gram
So
For 1 gram kanamycin = 5 ml of water is required
For 0.7 gram kanamycin = 0.7 x 5 ml of water is required
= 3.5 ml
Then ,0.7 g of water will be sterile by = 3.5 ml
