Answer:
Step-by-step explanation:
(x) = (1100 + x) (100 - .05(x-1100)) 
This is a quadratic, graphs as a parabola that opens downward. A maximum cam be found. 
The zeros of the function are 
(1100 + x) = 0 ..... or ..... [100 - .05(x-1100)] = 0 
x = -1100 is the left x-intercept. 
[100 - .05(x-1100)] = 0 
100 = .05(x-1100) 
2000 = x - 1100 
x = 3100 is the right intercept. 
Maximization of profits is at the mid point of the zeros (x-intercepts) 
(3100 + -1100)/2 = 1000 
1100 + 1000 = 2100 trees should be planted to maximize profits. 
f(x) = (1100 + 1000) (100 - .05(1000-1100)) 
f(x) = (2000) (105) = 220,500 is the maximum profit. 
I hope this helps!