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Luda [366]
2 years ago
5

More i-readyyyyyyyyyyy

Mathematics
2 answers:
Luda [366]2 years ago
8 0

Answer:

multiply 1/2 and 1/2 = 1/4 or .25

Step-by-step explanation:

Ksenya-84 [330]2 years ago
3 0

Answer:

1/4

Step-by-step explanation:

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Perform the indicated operation and simplify. (x+3)(x2−5x+2) Write your answer in standard form. No spaces when entering your an
Deffense [45]

Answer:

x^3-2x^2-13x+6

Step-by-step explanation:

We are to simplify the expression (x+3)(x^2−5x+2). This is as shown;

(x+3)(x^2−5x+2)

Expand

= x(x^2)-5x(x)+2x+3x^2-3(5x)+6

= x^3 - 5x^2+2x+3x^2-15x+6

Collect the like terms

= x^3 - 5x^2+3x^2+2x-15x=6

= x^3-2x^2-13x+6

This gives the required expression

6 0
3 years ago
house numbers on one side of a street are consecutive even integers. the sum of the first three house numbers on the street is 6
Vanyuwa [196]
Consecutive even integers..x, x + 2, x + 4

x + (x + 2) + (x + 4) = 6216
3x + 6 = 6216
3x = 6216 - 6
3x = 6210
x = 6210/3
x = 2070

x + 2 = 2070 + 2 = 2072
x + 4 = 2070 + 4 = 2074 <===house 3
4 0
3 years ago
PLEEASSEEEE Answer ASAP. Due in 5 Minutes. 25 points!!!!!!!!!
jonny [76]

Answer:

Here we will use the relationships:

a^n*a^m = a^{n + m}

(a^n)^m = a^{n*m}

\frac{a^n}{a^m} = a^{n - m}

And a number:

a^n

is between 0 and 1 if a is positive and larger than 1, and n is negative.

if a is positive and 0 < a < 1, then we need to have n positive such that:

0 < a^n < 1

A) 5^3*5^{-4} = 5^{3 + (-4)} = 5^{-1}

This is between zero and 1,

B) \frac{3^5}{3^{-6}} = 3^{5 - (-6)} = 3^{11}

This is greater than 1, because the exponent is positive.

C) (\frac{1}{4})^3*( \frac{1}{4})^2 = (\frac{1}{4})^{2 + 3} = (\frac{1}{4})^5

Because a is smaller than 1, and the exponent is positive, then the expression is between 0 and 1.

D) \frac{(-7)^5}{(-7)^7} = (-7)^{5 - 7} = -7^{-2}

The exponent is negative (and pair) then the expression is between 0 and 1.

Remember that when the exponent is pair, we always have that:

(-N)^m = (N)^m

So (-7)^-2 = 7^-2

4 0
3 years ago
Diane uses 2 feet of ribbon to decorate each gift she is wrapping. She wraps 7 gifts. How much ribbon does she need?
lakkis [162]
14, because 2x7=14. Every gift box uses 2 feet on ribbon. There are 7 gift boxes, so she needs 2+2+2+2+2+2+2 length of ribbon.
5 0
4 years ago
A supermarket had bags of red grapes for $13.00 for 5 bags. They also had bags of green grapes priced at $5.08 for 2
boyakko [2]

Answer:

Green grapes are less expensive.

Step-by-step explanation:

5.08/2 = 2.54

Multiply that by 5

You get $12.70 for 5 bags.

6 0
3 years ago
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