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STALIN [3.7K]
2 years ago
7

Researchers conducted a study to find out if there is a difference in the use of ereaders by different age groups. randomly sele

cted participants were divided into two age groupsin the to 29year-old group7% of the 628 surveyed use ereaders, while 11of the 2,309 participants 30 years old and older use ereaders(use subscripts let 1 16- to 29-year-old users , and 230 years old and
Mathematics
1 answer:
ikadub [295]2 years ago
4 0

No, there is significant difference in the use of e readers by different age groups.

Given sample 1 ( 29 years old) n_{1}=628, p_{1}=7%, sample 2( 30 years old)n_{2}=2309, p_{2}=0.11.

We have to first form hypothesis one null hypothesis and other alternate hypothesis.

H_{0}:π1-π2=0

H_{1}:π1-π2≠0

α=0.05

Difference between proportions p_{1}-p_{2}  =-0.04

p_{d}=0.07-0.11=-0.04

The pooled proportion needed to calculate standard error is:

p=(X_{1} -X_{2} )/(n_{1} +n_{2} )

=(44+254)/(628+2309)

=0.10146

The estimated standard error of difference between means is computed using the formula:

S_{p_{1} -p_{2} }=\sqrt{p(1-p)/m_{1}+p(1-p)/n_{2}  }

=\sqrt{0.101*0.899/628+0.101*0.899/2309}

=\sqrt{0.000143+0.00003}

=\sqrt{0.000173}

=0.01315

Z= Pd-(π1-π2)/S_{p_{1} -p_{2} }

=-0.04-0/0.013

=-3.0769

This test is a two tailed test so the p value for this test is calculated as (using z table)

p value:2 P(Z<-3.0769)

=2*0.002092

=0.004189

P value< significance level of 5%.

Hence there is enough evidence to show the claim that there is a significant difference in the use of e readers by different age groups.

Learn more about hypothesis at brainly.com/question/11555274

#SPJ4

Question is incomplete as it also includes:

Significance level of 5%.

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<h3>Answer:    x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

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So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

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