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3 years ago

12

Task: Volume & Surface Area

1 answer:

Triss [41]3 years ago

3 0

Okay so starting off I get that this math can be really confusing but you’ll get it if you keep working at it. Don’t give up you got this. For part it it is asking for the volume in cubic feet to do this you multiple H•W•L

H=hight

W=Width

L=Length

Now you don’t really need to know exactly which side is the H,L, or W but since you only have 3 sides with domentions you know that you multiply all three sides now it doesn’t matter what order you do it in.

Please respond if this helped for part A. You got this keep your head up.

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The area of a triangle is 24 square inches. What is the height of the triangle if the base length is 4 inches?

snow_tiger [21]

A = b*h*0.5
24 = 4*0.5*h
24 = 2*h
h = 12

Height is 12 inches.

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The number of customers that visit a local small business is 51,200 and has been continuously declining at a rate of 3.8% each y

Hunter-Best [27]

Answer:

Final amount of customers =30141.44

Step-by-step explanation:

Amount of customer remaining

A= p(1-r/n)^(nt)

P= initial amount of customers

R= rate but it's a negative rate

N= number of times

T= number of years

A= final amount of customers

A= p(1-r/n)^(nt)

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3 years ago

the length of a rectangle is five times the width. if the area of the rectangle is 125 square inches, find the length and width

Mekhanik [1.2K]

Length: 25
Width: 5
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Tina earned $300. This amount represented 40% of the money she needed to pay for her senior trip. What is the cost of the senior

ludmilkaskok [199]

Answer:

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3 years ago

Make a rational equations with the following requirements

Rufina [12.5K]

Answer:

$f(x)=\dfrac{-50(x-1)(x-2)}{(x-5)(x+5)}$

Step-by-step explanation:

Since f(x) has asymptotes at x = 5 and x = -5, then the denominator of the rational function contains the terms (x - 5) and (x + 5):

$f(x)=\dfrac{?}{(x-5)(x+5)}$

Since f(x) has x-intercepts at x = 2 and x = 1, then the numerator of the rational function contains the terms (x - 2) and (x - 1):

$f(x)=\dfrac{A(x-1)(x-2)}{(x-5)(x+5)}$

Now substitute the point (0, 4) and solve for A:

$f(0)=4\\\\\implies \dfrac{A(0-1)(0-2)}{(0-5)(0+5)}=4\\\\\\\implies -\dfrac{2}{25}A=4\\\\\\\implies A=-50$

So final rational function:

$f(x)=\dfrac{-50(x-1)(x-2)}{(x-5)(x+5)}$

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3 years ago