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2 years ago

What is the surface area of this cylinder ?

Mathematics

1 answer:

Lana71 [14]2 years ago

8 0

Answer:

87.92 mm²

Step-by-step explanation:

Given:

Radius of circular base: 2 millimeters
Height of cylinder: 5 millimeters

It should be noted:

Surface area of cylinder: 2πrh + 2πr² (R = Radius; H = Height)

When the measures are substituted, we get the following expression:

⇒ 2π(2)(5) + 2π(2)²

Multiply the constants and substitute π as 3.14.

⇒ 20π + 2π(4)
⇒ 20π + 8π
⇒ 20(3.14) + 8(3.14)

Finally, simplify the expression to determine the surface area.

⇒ 20(3.14) + 8(3.14)
⇒ 62.8 + 25.12
⇒ 87.92 mm²

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kiruha [24]

Answer:

Part A) $V(t)=-5,750t+101,250$

Part B) $\$55,250$

Step-by-step explanation:

Part A) Express the value of the bulldozer, V, as a function of how many years old it is, t.

Let

V ----> the value of the bulldozer (dependent variable or output value)

t ----> the number of years (independent variable or input value)

we know that

The linear function in slope intercept form is equal to

$V(t)=mt+b$

we have the ordered pairs

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Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute

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$m=-\$5,750\ per\ year$ ----> is negative because is a decreasing function

The value of b is the initial value

$b=\$101,250$

substitute

$V(t)=-5,750t+101,250$

Part B) The value of the bulldozer after 8 years is

For t=8 years

substitute the value of t in the linear equation

$V(t)=-5,750(8)+101,250=\$55,250$

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