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3 years ago

Two cities are 3 1/2 inches apart on a map the map scale says that 1/4 inch is 1 mile how many miles apart are the two cities

Mathematics

1 answer:

maria [59]3 years ago

7 0

Answer:

every 1/4 inch on the map is 1 mile.

You need to find the number of 1/4 inches there are in 3 1/2 inches.

There are four 1/4 inches per inch.

3 x 4 = 12

There are two 1/4 inches in 1/2 inch.

12+2 = 14

The cities are 14 miles apart.

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bekas [8.4K]

Answer:

Step-by-step explanation:

The right triangle on the right side of the figure has a height of 6 (two same sides lengths) and a base of 3.

x is the hypotenuse (side opposite of 90 degree angle).

We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

$6^2 + 3^2 = x^2\\36 + 9 = x^2\\45 = x^2\\x=\sqrt{45}$

Now we can use property of radical $\sqrt{x}\sqrt{y} =\sqrt{x*y}$ to simplify:

$x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}$

Correct answer is C

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3 years ago

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3 years ago

These rational expressions all have the same denominator write the sum of their numerators over the common denominator 2x+1 + x

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Brittany has 50 beads. 70% of the beads are gold. How many beads does Brittany have?

Ket [755]

Answer: 35 gold beads and 15 non-gold beads

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3 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

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4 years ago