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nexus9112 [7]
3 years ago
11

can someone help me with the circumferences and other stuff on this picture please (zoom out to see the full picture)

Mathematics
1 answer:
Daniel [21]3 years ago
8 0
The corcumference C of a circle is C= 2 x pie x radius
So radius= C/(2pie)

Volume of cylinder= pie x r(squared) x h
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Solve for x:<br> 600<br> x + 124<br> Just enter the number.
Kryger [21]
Answer: -4. Reasoning: We are trying to get the angle of both lines to equal 180. If you add 60+124 together to see how much we have currently, your answer comes up to 184. That’s 4 over what we need, therefore, -4 would be needed to bring the current amount back down to 180.
3 0
3 years ago
I’m not tryna fail lolll help
RoseWind [281]
Your not tryna fail so all you gotta do is act dumb noo
3 0
3 years ago
5c+ 3 &lt; 28 or -4c-2&lt; 14 for c.
sweet-ann [11.9K]

Answer:

c<5, and  c>-4.

<u>Steps used for answers:</u>

5c+3<28 =

1. Subtract 3 from both sides.

5c<28-3

2. Simplify  28-3 to  25.

5c<25

3. Divide both sides by 5.

c<25/5

4. Simplify  25/5 to 5.

c<5

-----------------------

-4c-2<14 =

1. Add 2 to both sides.

-4c<14+2

2. Simplify  14+2 to 16.

-4c<16

3. Divide both sides by -4.

c>-16/4

4. Simplify 16/4 to 4.

c>−4

<u>Done by NeighborhoodDealer</u>

3 0
3 years ago
Read 2 more answers
What is 23/25 in decimal
Ainat [17]
0.92 you would simply divide 23 by 25
7 0
3 years ago
Read 2 more answers
Please help with this question!!
xxMikexx [17]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\\\\l\perp k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have the points J(-24, -4) and K(-4, 6)}.\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{substitute:}\\\\m_1=\dfrac{6-(-4)}{-4-(-24)}=\dfrac{10}{20}=\dfrac{1}{2}\\\\\text{therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2\\\\\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{substitute the coordinates of the points J and K:}

x=\dfrac{-24+(-4)}{2}=\dfrac{-28}{2}=-14\\\\y=\dfrac{-4+6}{2}=\dfrac{2}{2}=1\\\\\text{midpoint}\ (-14,\ 1)\\\\\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\\text{substitute}\ m=-2,\ x_1=-14\ \text{and}\ y_1=1:\\\\y-1=-2(x-(-14))\\\\\boxed{y-1=-2(x+14)}

8 0
3 years ago
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