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KengaRu [80]
2 years ago
6

8) Choose the correct linear system of inequalities for the graph given.

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

Answer:

To graph a linear inequality in two variables (say, x and y ), first get y alone on one side. Then consider the related equation obtained by changing the inequality sign to an equality sign. The graph of this equation is a line.

If the inequality is strict ( < or > ), graph a dashed line. If the inequality is not strict ( ≤ or ≥ ), graph a solid line.

Finally, pick one point that is not on either line ( (0,0) is usually the easiest) and decide whether these coordinates satisfy the inequality or not. If they do, shade the half-plane containing that point. If they don't, shade the other half-plane.

Graph each of the inequalities in the system in a similar way. The solution of the system of inequalities is the intersection region of all the solutions in the system.

Example 1:

Solve the system of inequalities by graphing:

y≤x−2y>−3x+5

First, graph the inequality y≤x−2 . The related equation is y=x−2 .

Since the inequality is ≤ , not a strict one, the border line is solid.

Graph the straight line.

Consider a point that is not on the line - say, (0,0) - and substitute in the inequality y≤x−2 .

0≤0−20≤−2

This is false. So, the solution does not contain the point (0,0) . Shade the lower half of the line.

Similarly, draw a dashed line for the related equation of the second inequality y>−3x+5 which has a strict inequality. The point (0,0) does not satisfy the inequality, so shade the half that does not contain the point (0,0) .

The solution of the system of inequalities is the intersection region of the solutions of the two inequalities.

Example 2:

Solve the system of inequalities by graphing:

2x+3y≥128x−4y>1x<4

Rewrite the first two inequalities with y alone on one side.

3y≥−2x+12y≥−23x+4−4y>−8x+1y<2x−14

Now, graph the inequality y≥−23x+4 . The related equation is y=−23x+4 .

Since the inequality is ≥ , not a strict one, the border line is solid.

Graph the straight line.

Consider a point that is not on the line - say, (0,0) - and substitute in the inequality.

0≥−23(0)+40≥4

This is false. So, the solution does not contain the point (0,0) . Shade upper half of the line.

Similarly, draw a dashed line of related equation of the second inequality y<2x−14 which has a strict inequality. The point (0,0) does not satisfy the inequality, so shade the half that does not contain the point (0,0) .

Draw a dashed vertical line x=4 which is the related equation of the third inequality.

Here point (0,0) satisfies the inequality, so shade the half that contains the point.

The solution of the system of inequalities is the intersection region of the solutions of the three inequalities.

Step-by-step explanation:

I got it right

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Question 12(Multiple Choice Worth 1 points)
daser333 [38]

The equation of a line is y=-1/4x-7, (option 1)

<h3>What is the equation of a line? </h3>

A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis.

<h3>How do you find the equation of a line?</h3>

Write the equation in the form y = mx + b to find the slope m and the y-intercept. This will allow you to graph the equation using the slope and y-intercept.

Given:-

Equation of the line is y=4x+8 

The point through which the line passes (-8,4).

here the slope of the line is m1=4

To find the perpendicular line we know the formula

m1*m2=-1

By putting the value of m1 we get m2= -1/4

By using the one-point formula of the line we have

=>(y-y1)=m2*(x-x1)

By putting the values of y1 and x1 we get

(y1,x1)=(-8,4)

=>(y+8)=-0.25*(x-4)

y+0.25x+7=0

Hence the desired equation of the line is y=-1/4x-7

To find more about the straight line equations visit :

brainly.com/question/25969846

#SPJ1

7 0
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