Calculate the perimeter of the segment of a circle of radius 8cm. If chord subtemds angle 98 degree at the center

While he was at the grocery store, Raymond purchased a box of candy for himself. On the way back to the dorm, he ate 1/2 of th

viva [34]

Answer:

6 chocolates

Step-by-step explanation:

If there was 2 chocolates left and he had just eaten a third that would mean he had eaten 1

That would mean there would have been three chocolates before he put away the groceries

Double that to make up for the chocolates eaten during the walk home = 6

7 0

3 years ago

Read 2 more answers

What is the approximate measure of the length of the tennis court, x?

Romashka-Z-Leto [24]

Answer:

78.0 ft

Step-by-step explanation:

pythagoras theorem =

a² + b² = c²

a² + 36² = 85.9²

a² + 1296 = 7378.81

a² = 7378.81 - 1296

a² = 6082.81

a = √6082.81

a = 77.992....

so, a (rounded) = 78 ft :)

3 0

3 years ago

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If s = -5 and t = 3, find the value of s 2 t. 225 75 30 -75

Reika [66]

Just answered this one a few minutes ago.

(-5)(-5)(3)= 75

7 0

4 years ago

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Explain how you can find the side length of a rectangular prism if you are given the volume in the two other measurements. Does

Kruka [31]

Let's remember that V = lwh. If you are given two other measurements, you can multiply those two and divide V by that quantity to solve for the missing variable. Same process no matter the value:)

6 0

3 years ago

In a survey, 32% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result

adoni [48]

Answer:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

$\hat p=\frac{61}{210}=0.29$ estimated proportion of pet owners contacted by telephone

$p_o=0.32$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:

Null hypothesis: $p \geq 0.32$

Alternative hypothesis: $p < 0.32$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

3 0

3 years ago