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3 years ago

Proving the Congruent Supplements Theorem

2 answers:

6 0

If two angles are each supplementary to a third angle, then they're congruent to each other. This is the three-angle version, Supplements of congruent angles are congruent. If ∠A + ∠T = 180° ∠C + ∠T = 180° then the angles are congruent.

I hope this helps you.

AleksandrR [38]3 years ago

4 0

Answer:

Congruent Supplements Theorem : If two angles are supplements of the same angles (or of congruent angles), then the two angles are congruent.

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Help me with these math questions.

Olegator [25]

graph A

no x-intercept

no y-intercept

H.A is y = 5

V. A. is x = 0

*****************************************

Answer: $\frac{150}{31}$

<u>Step by step explanation:</u>

log₆(5x + 6) - log₆(x - 4) = 2

log₆ $(\frac{5x+6}{x-4})$ = 2

$(\frac{5x+6}{x-4})$ = 6²

$(\frac{5x+6}{x-4})$ = 36

5x + 6 = 36(x - 4)

5x + 6 = 36x - 144

6 = 31x - 144

150 = 31x

$\frac{150}{31}$ = x

**********************************************************

Answers:

a. (-1, -5)
b. up
c. x = -1
d. $\frac{-2+\sqrt{15}}{3} and\frac{-2-\sqrt{15}}{3}$
e. -2
f. see attachment
g. domain (-∞, ∞) range [-5, ∞)

<u>Explanation:</u>

f(x) = 3x² + 6x - 2

a=3 b=6 c=-2

x = $\frac{-b}{2a} =\frac{-6}{2(3)} = \frac{-6}{6} = -1$

Axis Of Symmetry: x = -1

f(-1) = 3(-1)² + 6(-1) - 2

= 3 - 6 - 2

= -5

Vertex: (-1, -5)

x = $\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

= $\frac{-6+/-\sqrt{6^{2}-4(3)(-2)}}{2(3)}$

= $\frac{-6+/-\sqrt{36+24}}{6}$

= $\frac{-6+/-\sqrt{60}}{6}$

= $\frac{-6+/-2\sqrt{15}}{6}$

= $\frac{-2+/-\sqrt{15}}{3}$

x-intercepts: $\frac{-2+/-\sqrt{15}}{3}$

6 0

3 years ago

Find the missing side. Round your answer to the nearest tenth

telo118 [61]

Answer:

14.7

Step-by-step explanation:

tan(73)=48/x

or, x=48/tan(73)

or, x=14.7 (rounded to the nearest tenth)

Answered by GAUTHMATH

6 0

3 years ago

Which statement is true about the expression?

zysi [14]

Answer:

Your number is (3 sqrt(2)) / sqrt(2) = 3, and is a rational number indeed. I don't know exactly how to interpret the rest of the question. If r is a positive rational number and p is some positive real number, then sqrt(r^2 p) / sqrt(p) is always rational, being equal r. Possibly your question refers to situtions in which sqrt(c) is not uniquely determined, as for c negative real number or complex non-real number. In those situations a discussion is necessary. Also, in general expressions the discussion is necesary, because the denominator must be different from 0, and so on.

Step-by-step explanation:

7 0

3 years ago

What is the product of 4x4y2 and 5y4?

Inessa05 [86]

Answer:

20 $x^{4}$ $y^{6}$