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babunello [35]
2 years ago
8

How many license plates can be made using three uppercase English letters followed by four digits

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
8 0
49
Because all three digits can be randomized and all of the following four digits can also be put into different place orders so that would mean since there are three uppercase English letters and four digits combined those together that makes seven in total randomize it seven times and you get 49 license plates
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When can there be a point equidistant from four different points?
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4 years ago
The mean work week for engineers in start-up companies is claimed to be about 63 hours with a standard deviation of 5 hours. Kar
Phantasy [73]

Answer:

a. Mean

b. μ = μ₀

c. 11.5%

d. Yes

Step-by-step explanation:

The given parameters are;

The mean work week for engineers, μ₀ = 63 hours

The standard deviation, σ = 5 hours

The number of engineers in Kara's sample, n = 10 engineers

The responses given by the 10 engineers are;

70; 45; 55; 60; 65; 55; 55; 60; 50; 55

a. The given information which the newly hired is hoping to find out that it is not is the <em>mean</em>

<em />

b. The null hypothesis which is that the company claim is correct, is therefore;

Null hypothesis, H₀; μ = μ₀ = 63 hours

c. Kara's mean, \overline x is found as follows;

\overline x = (70 + 45 + 55 + 60 + 65 + 55 + 55 + 60 + 50 + 55)/10 = 57

\overline x = 57 hours

The Z-score is therefore;

Z=\dfrac{\overline x-\mu }{\sigma }

Z = (57 - 63)/5 = -1.2

From the Z-table, we have;

The p-value for P(\overline x ≤ 57) =  P(Z ≤ -1.2) = 0.11507

The probability as a percentage given to one decimal place, that the mean would be as low as Kara's mean, P(\overline x ≤ 57) = 11.5%

d. Given that the percent percentage chance (11.5%) that the mean could be as low as hers (\overline x = 57 hours) is higher than 10%, she should accept the claim.

3 0
3 years ago
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bija089 [108]

Answer: 4a

<u>Step-by-step explanation:</u>

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 ∧    ∧                           ∧  ∧                          ∧   ∧

2  6  a² b⁶                    7 4  aaaa                 7 6 a b³

   ∧     ∧                          ∧                              ∧     ∧

  2 3  aa bbbbbb          2 2                           2 3   bbb

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GCF = 2 * 2 * a = 4a          

6 0
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