You multiply the length and the width if it is a square. if you give the shape i can be more specific
Answer:
or
.
Step-by-step explanation:
Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.
The total number of cards in a deck 52
Number of faces cards in a deck = 12
Number of cards not face cards = 40
The total number of combinations of drawing 9 cards out of 52 cards = 
Now , the combination of 9 cards such that exactly 6 of them are face cards = 
Now , the probability that the hand contains exactly 6 face cards will be :-

![=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Cdfrac%7B12%21%7D%7B6%216%21%7D%5Ctimes%5Cdfrac%7B40%21%7D%7B3%2137%21%7D%7D%7B%5Cdfrac%7B52%21%7D%7B9%21%5Ctimes43%21%7D%7D%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B228%7D%7B91885%7D)
Hence, the probability that the hand contains exactly 6 face cards. is
.
That is false, miss. It IS the radius.
Answer:
(5, 7 )
Step-by-step explanation:
Given 2 points (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]
here (x₁, y₁ ) = U(8, 9) and (x₂, y₂ ) = V(2, 5), thus
midpoint = [0.5(8 + 2), 0.5(9 + 5) ] = [0.5(10), 0.5(14) ] = (5, 7 )
Idk boiiiiiii ok actually all you do is use a couculater