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2 years ago

Help me pleasehelp me please

Mathematics

1 answer:

Nikolay [14]2 years ago

7 0

Answer:

1 second

Step-by-step explanation:

$s=-5\\u=0\\v=\\a=-10\\t=t$

$\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}$

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Using the variables 'x' and 'y', write an equation for the situation. Your school sold adult and student tickets for a high scho

tiny-mole [99]

X+y=782

Is there any other info given or no?

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3 years ago

Read 2 more answers

4. The cube root parent function is vertically stretched by a factor of 3, reflected in the x-axis,

Mademuasel [1]

Using translation concepts, it is found that the equation that represents the new function is:

$y = -3\sqrt[3]{x} - 8$

The cube root parent function is given by:

$y = \sqrt[3]{x}$

<h3>Translation:</h3>

The function goes through these following translations:

Vertically stretched by a factor of 3, that is, it is multiplied by 3, hence $y = 3\sqrt[3]{x}$ .

Reflected over the x-axis, that is, it is multiplied by -1, hence $y = -3\sqrt[3]{x}$ .

Translated 8 units down, that is, 8 is subtracted from the function, hence $y = -3\sqrt[3]{x} - 8$ .

Then, the equation is:

$y = -3\sqrt[3]{x} - 8$

To learn more about translation concepts, you can take a look at brainly.com/question/13671886

3 0

2 years ago

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime

Aleks [24]

Answer:

Its A

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Re-write the equation without the h component.

levacccp [35]

Answer:

$f(x) = 2[\frac{3^x}{9}] + 2$

$f(x) = 8(4)^x$

Step-by-step explanation:

Given

$f(x) = 2(3)^{x-2} + 2$

$f(x) = \frac{1}{2}(4)^{x+2}$

Required

Remove the h component

In a function, the h component is highlighted as:

$f(x) = a^{x+h}$

So, we have:

$f(x) = 2(3)^{x-2} + 2$

Split the exponents using the following law of indices:

$a^m/a^n = a^{m-n}$

$f(x) = 2*\frac{3^x}{3^2} + 2$

$f(x) = 2*\frac{3^x}{9} + 2$

$f(x) = 2[\frac{3^x}{9}] + 2$

<em>The h component has been removed</em>

$f(x) = \frac{1}{2}(4)^{x+2}$

Split the exponent using the following law of indices

$a^{m+n} =a^m * a^n$

So, we have:

$f(x) = \frac{1}{2}(4)^x * 4^2$

Express 4^2 as 16

$f(x) = \frac{1}{2}(4)^x * 16$

Divide 16 by 2

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3 0

2 years ago

Solve the system of equations using the substitution method. 2x+8y=4 x=−3y+5

goldenfox [79]

Since x=-3y+5, substitute x for -3y+5.

2(-3y+5)+8y=4

Distribute.

-6y+10+8y= 4

2y+10= 4

Subtract 10 on both sides.

2y=-6

Divide by 2.

y=-3

Plug in y=-3.

x=-3(-3)+5
x= 9+5
x=14

(14,-3)

We can check this.

2(14)+8(-3)=4
28-24=4
4=4 <== this works

I hope this helps!
~kaikers

7 0

3 years ago

Help me pleasehelp me please​

Help me pleasehelp me please